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Joe Ricard
Joined: 23 Jun 2009 Posts: 865 Location: United States, Mississippi,
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Posted: Mon Oct 22, 2012 12:44 pm Post subject: |
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Pretty spiffy graph with the vertical numbers missing.
My Vortex RVS was supposed to make 42 HP when new.
I see the chart for the Honda claiming the same.
So what are the KZ's making nowadays. _________________ Arrow AX-8/ Rotax Sr. |
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Tim Salvino
Joined: 20 Nov 2010 Posts: 257
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Posted: Mon Oct 22, 2012 12:48 pm Post subject: |
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| Joe Ricard wrote: | | So what are the KZ's making nowadays. |
On whose dyno?
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Joe Ricard
Joined: 23 Jun 2009 Posts: 865 Location: United States, Mississippi,
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Posted: Mon Oct 22, 2012 1:10 pm Post subject: |
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Yea, I know. Would like to put them all up on the same dyno someday. _________________ Arrow AX-8/ Rotax Sr. |
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Steve Buckner
Joined: 22 Apr 2003 Posts: 839
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Posted: Mon Oct 22, 2012 2:03 pm Post subject: |
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| Jason Berry wrote: | | Mike Goebel wrote: | Why no HONDA??
Mike G. |
They're all the same, I will let Steve post his. I don't want to hog up the thread. |
| Jason Bell wrote: |  |
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Mike Goebel
Joined: 28 Jul 2001 Posts: 5765 Location: United States, California, Winnetka
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Posted: Mon Oct 22, 2012 7:33 pm Post subject: |
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To get the shift point right one must graph velocity vs HORSE POWER for all gears and find where the HORSE POWER curves cross. Then back calcutate RPM.
Lets say at 26MPH you see the curves for 1st to 2nd cross, just find out what RPM the engine is at 26MPH and you have your shift point.
Don't try to shoot holes in this method, it is PERFECT!!!
Mike G. _________________ Closet KZ Lover!!!
mfg Technology Centre
So Cal’s #1 Non Profit Engine Builder |
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Jim McMahon
Joined: 07 Apr 2007 Posts: 2665 Location: United States, St. Paul,
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Jason Berry Advertiser

Joined: 29 Dec 2001 Posts: 294
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Tom Barth
Joined: 22 Oct 2001 Posts: 1379 Location: United States, Michigan, Waterford
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Posted: Sun Oct 28, 2012 6:21 am Post subject: |
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In my humble opinion, the properly set up KZ has only one power band. It is in the design and no amount 'tuning' will change it! This assumes that the timing and carburetion is correct.
If maximum performance is desired then adherence to the homologation specs is very important i.e. port timing and any other spec that is flexible. _________________ Tom Barth
http://www.greenflagkarting.com/
Power is good...more power is better... too much power is just right! |
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al nunley
Joined: 13 Nov 2006 Posts: 3030
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Posted: Sun Oct 28, 2012 8:25 am Post subject: |
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| Jim McMahon wrote: | | It depends on the gear ratios and the powerband of the motor. Depending on the curve and the next gear ratio it can actually be beneficial to engage the next gear below or above peak torque. |
I just can’t see how having less torque at the rear axle could be “beneficial”??
Does it have something to do with the gear ratios?
Maximum torque at the rear axle means maximum HP at the rear axle. In what scenario would that be bad? _________________ If the data does not support the theory, get a new theory. (Al Nunley)
All else being equal; Compression is the Holy Grail.
45 years, in and around karting |
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al nunley
Joined: 13 Nov 2006 Posts: 3030
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Posted: Sun Oct 28, 2012 9:21 am Post subject: |
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[quote="Mike Goebel"]To get the shift point right one must graph velocity vs HORSE POWER for all gears and find where the HORSE POWER curves cross. Then back calcutate RPM.
Interesting, but I think you might be forgetting something; HP is a calculation, torque is what get’s the job done. All you get to the rear axle is torque, (there is no HP going thru the transmission, only torque.) you then multiply that by the axle RPM, then divide that total by 5252.1 and you get HP.
Not that HP isn’t important, it is, but it’s HP at the axle that’s important, not at the engine, and it is different.
Think of this, let’s say the engine is turning 11,500 RPM, near peak HP, but you’re in third gear, with a ratio of, lets say, just for this discussion, 3-1. And lets say that the axle is turning, (again, just for discussion) 1500 RPM. Again, just for discussion, at that RPM the engine is producing 20ft lbs of torque. So the engine is producing 11,500 X 20 / 5252.1 = 43.79 HP. The torque is multiplied by 3, so the axle is seeing 60lbs of torque. 1500 X 60 / 5252.1 = 17.14HP
Now let’s use the engine RPM at peak torque, let‘s say 30ft lbs at 10,500. Thru the 3-1 ratio means 90ft lbs. at the axle. 1500 X 90 / 5252.1 = 25.7 HP at the rear axle
Just numbers I dreamed up, but use the real numbers and you’ll find pretty much the same thing, or close. _________________ If the data does not support the theory, get a new theory. (Al Nunley)
All else being equal; Compression is the Holy Grail.
45 years, in and around karting |
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Jim McMahon
Joined: 07 Apr 2007 Posts: 2665 Location: United States, St. Paul,
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Mike Goebel
Joined: 28 Jul 2001 Posts: 5765 Location: United States, California, Winnetka
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Posted: Mon Oct 29, 2012 6:27 pm Post subject: |
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HP at engine = HP at rear wheels minus some frictional losses.
Assume single gear kart
Example
Engine
12,000 RPM and 30HP
Torque = 30HP*5252/12,000RPM = 13.13 ft-lb at the engine
Rear axle ratio = 1/3
Rear axle is turning 1/3 speed so....
Axle speed is 4,000 RPM
Rear Axle see 3 times the torque (see where this is going??)
Wait you ask if you increase torque by 3 but reduce speed by 3 then you have no change in HP
Power is conserved minus friction losses. THIS IS THE LAW.
What law you ask??? the law of conservation of energy.
Click here ---> THE LAW
Mike G.
Any mathematical mistakes are trival!! _________________ Closet KZ Lover!!!
mfg Technology Centre
So Cal’s #1 Non Profit Engine Builder |
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Brian Degulis
Joined: 13 Aug 2012 Posts: 414 Location: United States, Florida,
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Posted: Fri Nov 02, 2012 5:00 am Post subject: |
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| Mike Goebel wrote: | To get the shift point right one must graph velocity vs HORSE POWER for all gears and find where the HORSE POWER curves cross. Then back calcutate RPM.
Lets say at 26MPH you see the curves for 1st to 2nd cross, just find out what RPM the engine is at 26MPH and you have your shift point.
Don't try to shoot holes in this method, it is PERFECT!!!
Mike G. |
That does sound perfect the question I have is how do you do it? If I understand you correctly you start with the engines power curve showing HP available at any given RPM. Then you would have to create a graph showing speed in MPH at specific RPMs maybe 100 RPM intervills in all six gears. Then you would overlay that on the power curve to determine shift points. Is that what your suggesting? If so how would you scale your MPH graph to acuratly overlay on the power curve?
Brian |
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Mike Goebel
Joined: 28 Jul 2001 Posts: 5765 Location: United States, California, Winnetka
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Posted: Fri Nov 02, 2012 6:27 am Post subject: |
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Plot HP vs MPH. Once you do that you will see where the curves cross. Find that point and back calcuate RPM. It's a kinda back and forth calc.
Since you have RPM you can find HP from the dyno curve (verticle axis) and you can calculate Speed (horzontal axis) from gear ratios.
Mike G. _________________ Closet KZ Lover!!!
mfg Technology Centre
So Cal’s #1 Non Profit Engine Builder |
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Brian Degulis
Joined: 13 Aug 2012 Posts: 414 Location: United States, Florida,
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Posted: Fri Nov 02, 2012 11:24 am Post subject: |
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OK I got it. That makes a lot of sense becuase if you go soley by the power curve your not factoring in the ratio from transmission to axle wheel diameter and momentem. On the other hand is it really possible to apply this in reall world driving? You'd have to be pretty focused on the tach.
Brian |
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